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If X + Y = XY^2, then what is the value of 3 + (t-1) ?
(a) 3t2 – 2t + 2.
(b) 3t2 – 2t + 4.
(c) 3t2 – 6t +3.
(d) 3t2 – 6t – 3.
(e) 3t2 – 6 + 3.
The best answer is C.
3 + (t-1) = 3(t-1)2 = 3(t2-2t+1) = 3t2 – 6t +3.
If Q+ = Q + 2, then what is the value of (3+)+ ?
(a) 7.
(b) 5.
(c) 6.
(d) 4.
(e) 8.
The best answer is A.
(3r)+ = (3 + 2)+ = 5+ = 5 + 2 = 7.
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